Math, asked by hfvjyxvkid, 1 year ago

solve ques no.24only plz

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Answered by manamperi344
1

I am going to go all the way and find the values of a and b here.

As (x - 1) is a factor of p(x) we have by the factor theorem that p(1) = 0.

Hence, 1^3 - a(1)^2 - 13(1) + b = 0 ⇒ a - b = -12      [1]

Similarly as (x + 3) is a factor of p(x), it follows that p(-3) = 0.

Hence, (-3)^3 - a(-3)^2 - 13(-3) + b = 0 ⇒ 9a - b = 12     [2]

Solving [1] and [2] simultaneously :

[2] - [1] : 8a = 24 ⇒ a = 3.

[1]: 3 - b = -12 ⇒ b = 9.

By the way, equations [1], [2] are the relations between a and b that can be deduced using the given information.


manamperi344: Yeah I believe b = 3a is completely fine.
hfvjyxvkid: ohk
manamperi344: Considering this is an exam question I think they did want you to get to b = 3a (rather than stopping after a - b = -12 for which you don't even need all the information in the question, even though it's still a "relation"), but I think the question needs to be clearer (like say give a relation in the form a = kb or something like that)
hfvjyxvkid: thnx a lot
manamperi344: No worries :)
hfvjyxvkid: is my ans. would be correct or not? in exam i hv done it
hfvjyxvkid: n ans is b=3a
hfvjyxvkid: by adding
hfvjyxvkid: both eq.
manamperi344: Yeah this is a valid answer to the question
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