Solve question 1 and 2
Attachments:
Answers
Answered by
1
we have
alpha=1/4
beta=-1
then, a equation is that,
x^2-(alpha+ beta)x+ ( alpha× beta)
x^2-(1/4+(-1))x+(1/4×-1)
x^2-3/4x+-1/4=0
4x^2-3x-1 is the required polynomial
alpha=1/4
beta=-1
then, a equation is that,
x^2-(alpha+ beta)x+ ( alpha× beta)
x^2-(1/4+(-1))x+(1/4×-1)
x^2-3/4x+-1/4=0
4x^2-3x-1 is the required polynomial
Answered by
1
here is ur answer hope this helps u
Attachments:
Sinhmaar:
ur welcome
Similar questions