Question

solve question 1 that's 10std

Answer 1

Solution :

Let x = a² + b² ,

y = a² - b² ,

z = 2ab ,

are three sides of a ∆XYZ

Now ,

x² = (a² + b² )²

y² = ( a² - b² )²

z² = (2ab)² = 4a²b²

y² + z²

= ( a² - b² )² - 4a²b²

= ( a² + b² )²

= x²

Therefore ,

y² + z² = x²

[Sum of the squares of any

two sides is equal to square

of the third side ]

XYZ is a Right ∆.

Examples :

( 3 , 4 ,5 ), ( 6,8,10 ) are

Phythogarian triplets.

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