Question

Solve question 10. and Question 13 both parts


Need step by step solution

Answer 1

10)

Since, the margin 1.5 m is left for planting, reduction in length and breadth would be 3 m, as it is left from both sides.

So, new Length = 21 - 3 = 18 m
New breadth = 17 - 3 = 14 m


Now, area for planting tuberoses = area of whole garden - area of new rectangle formed

Area of whole garden = 21 × 17 = 357 m²

Area of new rectangle = 18 × 14 = 252 m²

So, area for planting = 357 - 252 = 105 m²

Now, 3 tuberoses can be planted in 1 m², so tuberoses that can be planted in 105 m² = 105/3 = 35

Answer :- 35


13)

a) To find area of shaded portion, subtract area of smaller circle from larger.

Area of larger = πr² = π × 4² = 16π cm²

Area of smaller = πr² = π × 3² = 9π cm²

=> Area of shaded = 16π - 9π = 7π cm²

Taking π as 22/7,

Area of shaded = 7 × 22/7 = 22 cm²

Answer :- 22 cm²

b) There are four quadrants made in a rectangle. The area of total 4 quadrant with same radius = area of circle of their radius

The radius of one quadrant = 70/2 = 35 cm

So, area of four quadrants = area of one circle

= 22/7 × 35 × 35

= 3850 cm²

Area of square = side × side = 70 × 70 = 4900 cm²

So, area of shaded = 4900 - 3850 = 1050 cm²

Answer :- 1050 cm²

Answer 2

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Question 10.

Solution:-

The margin 1.5 m is left for planting, reduction in length and breadth would be 3 m, as it is left from both sides.

So,

New Length = 21 - 3 = 18 m

New breadth = 17 - 3 = 14 m

Now, Area for planting tuberoses = Area of whole garden - Area of new rectangle formed.

Area of whole garden

=> 21 × 17 = 357 m²

Now, Area of new rectangle

=> 18 × 14 = 252 m²

So, Area for planting

=> 357 - 252 = 105 m²

Now, 3 tuberoses can be planted in 1 m².

So, tuberoses that can be planted in 105 m² = 105/3 = 35.

[Answer :- 35]

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Question 13.

Solution:-

a)

Solution:-

To find the area of the shaded portion, subtract area of smaller circle from larger.

Area of larger

=> πr² = π × 4² = 16π cm²

Area of smaller

=> πr² = π × 3² = 9π cm²

Area of shaded

=> 16π - 9π = 7π cm²

Taking π as 22/7,

Area of shaded

=> 7 × 22/7 = 22 cm²

[Answer :- 22 cm²]

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b)

Solution:-

There are 4 quadrants made in a rectangle. The area of the total 4 quadrant with same radius = Area of circle of their radius.

The radius of one quadrant = 70/2 = 35 cm

So, area of four quadrants = area of one circle

= 22/7 × 35 × 35

= 3850 cm²

Area of square

=> Side × Side= 70 × 70 = 4900 cm²

So, area of shaded

=> 4900 - 3850 = 1050 cm²

[Answer :- 1050 cm²]

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