Question

Solve question 12 . With steps. Very important

Answer 1

For angle ABD:-
In triangle AOB
angle AOB = anlgle DOC = 65 (Vertically opposite angle)
so angle AOB + angle BOA + angle ABD = 180 
65 + 35 + angle ABD = 180
angle ABD = 180 - 100
angle ABD = 80

For angle BDC:-
angle BDC = ABD = 80 (Alterante interior angles)

For angle ACB :-
angle ACB = angle CAD = 40 (alternate interior angles)

For angle CBD :-
angle DOC = angle OCB +angle OBC (triangle exterior angle theorem)
65 = 40 + angle OBC
25 = angle OBC
angle CBD = angle OBC + angle ABD
angle CBD = 25 + 80
angle CBD = 105

I hope this will help you.