Solve question 21 please.
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area of quadrant = pie r(sqr)/4
=(22/7 × 6×6 )/4
=198/7
area of shaded region= area of quadrant - area of traingle odb
=198/7 - 12
= 114/7
=(22/7 × 6×6 )/4
=198/7
area of shaded region= area of quadrant - area of traingle odb
=198/7 - 12
= 114/7
Answered by
1
hey buddy here is your answer for Q no.21.
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