Solve question 4 and 5 both with process.
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4. As vertically opposite ansgles are equal so, let each angle be x
x + x = 96°
2x = 96°
x = 96°/2 or 48°
5. When OB is perpendicular to OA then
/_ AOB = 90°
/_ AOB = /_ BOC + /_ AOC
90° = 50° + /_ AOC
40° = /_ AOC
Now,
/_ AOC + /_ AOD = 180° [ Linear Pair ]
/_ AOD = 180° - 40°
/_ AOD = 140°
Hope it helps
4. As vertically opposite ansgles are equal so, let each angle be x
x + x = 96°
2x = 96°
x = 96°/2 or 48°
5. When OB is perpendicular to OA then
/_ AOB = 90°
/_ AOB = /_ BOC + /_ AOC
90° = 50° + /_ AOC
40° = /_ AOC
Now,
/_ AOC + /_ AOD = 180° [ Linear Pair ]
/_ AOD = 180° - 40°
/_ AOD = 140°
Hope it helps
Answered by
1
Question 4
Opposite angles are the same so each of the angles are:
96° ÷ 2 = 48°
Question 5
Find the angle of COA first:
90° - 50° = 40°
Since COD is a straight line, the angles on it are equal to 180°.
∠AOD + 40° = 180°
∠AOD = 140°
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