Solve Question 5
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5) A
first term (a) = 33
d =4
let n terms be taken so that their sum is1206
n/2 x (2xa + (n-1 )d = 1206
n/2 x (2x33 +(n-1)4= 1206
n/2 x (66-4 +4n) = 1206
n(4n + 62)= 2412
4nxn + 62n - 2412=0
now can solve it
6)A
perimeter of rectangle =2(l+b )
104=2(x+b)
x+b= 52
b= 52-x ---------(!)
now, areaof rectangle = lb
x(52-x)= 640. (using (!) )
--------------------------------
! 52x -xsquare = 640. !
----------------------------------- now you can solve it
5)c
first term (a) = 33
d =4
let n terms be taken so that their sum is1206
n/2 x (2xa + (n-1 )d = 1206
n/2 x (2x33 +(n-1)4= 1206
n/2 x (66-4 +4n) = 1206
n(4n + 62)= 2412
4nxn + 62n - 2412=0
now can solve it
6)A
perimeter of rectangle =2(l+b )
104=2(x+b)
x+b= 52
b= 52-x ---------(!)
now, areaof rectangle = lb
x(52-x)= 640. (using (!) )
--------------------------------
! 52x -xsquare = 640. !
----------------------------------- now you can solve it
5)c
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anaghachavan81:
Can you show the steps for Q5 C and solve Q5 B)
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