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Answers
Solution
Given :-
- Two circuit are A. & B. , where some resister connected in parallel & series .
Find :-
- Effective Resistance of both circuit .
Explanation
In First Circuit
R¹ , R² & R³ connected in series ,
then effective Resistance will be 1/R
Using Formula
==> 1/R = 1/R¹ + 1/R² + 1/R³
Keep all above Values,
==> 1/R = 1/90 + 1/45 + 1/180
==> 1/R = (2 + 4 + 1)/180
==> 1/R = 5/180
==> 1/R = 1/36
Or,
==> R = 36 Ohm
___________________________
In Second circuit
R1 & R⁴ connected in series & R² & R³ connected in Parallel.
We Know,
==> 1/R' = 1/30 +1/50
==> 1/R' = (50 +30)/1500
==> 1/R' = 80/1500
==> 1/R' = 8/150
Or,
==> R' = 150/8
==> R' = 18.75
Now Calculate series , and R' now also perform as a series resistance,
==> R = 18.75 + 20 + 20
==> R = 58.75 ohm
Hence
- Effective Resistance of first circuit = 36 ohm
- Effective Resistance of second Circuit = 58.75 ohm
___________________
1) Rs = R1 + R2 + R3
= 90 + 45 + 180
Rs = 315//
V = IR
9 = I(315)
9/315 = I
0.028 = I
2) Rs = R1 + R2 + R3 + R4
= 20 + 30 + 50 + 20
Rs = 120//
V = IR
10 = I (120)
10/120 = I
0.083 = I
TOTAL RESISTANS IS
R = Rs + Rs
R = 315 + 120
R = 435//