Question

solve question in the above figure

Answer 1

C ) 4.0 .
plz follow me
its humble request

Answer 2

As CH3COOH is a stronger acid than ethyl alcohol.then Et alcohol will act as a base.
Reaction----
CH3COOH+EtOH <------> EtOH2+ + CH3COO-.
NOW.
initially you have 4.6 g of EtOH = 0.1 moles of EtOH. & 6g of CH3COOH = 0.1 moles of CH3COOH.
AT EQUILIBRIUM:
moles of CH3COOH left = 2/60=1/30 moles.
hence moles consumed in rxn = 0.1-1/30=2/30.
hence moles(= concentration here) at equilibrium:
[Acetic acid]=1/30
[EtOH]=0.1-2/30= 1/30.
[EtOH2+]= 2/30= [CH3COOH]
HENCE Kc =[(2/30)×(2/30)]÷[(1/30)×(1/30)]
= 4.0.