Question

solve question log 3x-1 to base5<1 then solve for x

Answer 1

$log_{5}(3x - 1) < 1 \\ \\ 3x - 1 < {5}^{1} \\ \\ 3x - 1 < 5 \\ \\ 3x < 5 + 1 \\ \\ 3x < 6 \\ \\ x < \frac{6}{3} \\ \\ x < 2$

$\boxed{ \textbf{ \large Answer: \: x < 2}}$

Answer 2

$\huge\mathcal{\fcolorbox{cyan}{black}{\pink{ĄNsWeR࿐}}}$

$log_{5}(3x - 1) < 1 \\ \\ 3x - 1 < {5}^{1} \\ \\ 3x - 1 < 5 \\ \\ 3x < 5 + 1 \\ \\ 3x < 6 \\ \\ x < \frac{6}{3} \\ \\ x < 2$

$\boxed{ \textbf{ \large Answer: \: x < 2}}$