Question

solve question no.1,2
chapter name: playing with numbers
formula : (10a+b)
plz .

Answer 1

Let the unit digit be x and ten digit is y.

Then the number is 10y + x. This number is 6 times of unit digit.

Hence 10y + x = 6x

10y- 5x = 0 -------(1)

Sum of the digits is 9

y +x = 9 ------------(2)

Solving (1) & (2) we will get x = 6 & y= 3

Then the number is 36.

Verify:

Sum of the digits = 6+3= 9

The number 36 is 6 times of unit digit i. e. 6x 6= 36.

Answer 2

Let the tens number be x and y be units digit

1.Given x + y = 9 ———>(1)
10x + y = 6y
=> 10x = 5y
=> x = 5y/10=y/2
Putting this value in eq. 1,
y/2 + y = 9
=>y/2 + 2y/2 = 9
=>3y = 18
=>y = 6.
=>x = 3.
Therefore,
No. is 36.


2.Given,
x + y = 7. ———>(1)
=>x = 7-y

Original number = 10x + y
New no. = 10y + x

Given,
10y + x +3 = 4(10x + y)
=>10y + x + 3 - 40x - 4y = 0
=>6y - 39x + 3= 0
=>2y - 13x = (-1) ———>(2)

(1) × 2 - (2)
After solving this,
x and y will be founded and
Original number will be founded.




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