solve question no 10
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let the one's digit be x and ten's digit be y
then original no.=10y+x______○1
now,ATQ
y=3+x______○2
again, ATQ
10x+y +10y+x=143
11y+11x=143
putting value of y in the above equation
11 (3+x)+11x=143
33+11x+11x=143
22x=110
x=110/22
x=5
putting value of x in eq 2
y=3+5=8
putting value of x and y in eq 1
original number=(10×8)+5
=>80+5
=>85
then original no.=10y+x______○1
now,ATQ
y=3+x______○2
again, ATQ
10x+y +10y+x=143
11y+11x=143
putting value of y in the above equation
11 (3+x)+11x=143
33+11x+11x=143
22x=110
x=110/22
x=5
putting value of x in eq 2
y=3+5=8
putting value of x and y in eq 1
original number=(10×8)+5
=>80+5
=>85
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