Math, asked by RISHABHYADAV2001, 1 year ago

Solve question no.10. For take brainliest................. .please.

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Answered by RahulCR7
0
A(a,b+c),B(B,c+a)& C(c,a+b)
x1(y2 - y3) + x2(y3 - y1) + x3(y2 - y1) = 0 \\ a(c + a - a - b) + b( a+b  - b - c) + c( b+ c -  a- c) =0 \\ a(c - b) + b(a - c) + c(b - a) = 0 \\ ac - ab + ab - cb + cb - ac = 0 \\ 0 = 0
hence all the points are collinear.
Answered by JOVIAL1001ash1
1
above is the solution
hope dis'll help u
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