Math, asked by santoshkumarmth49, 4 months ago

solve question no.11 and 12​

Attachments:

Answers

Answered by alok12318
2

 \boxed{ \boxed{ \bf \red{</p><p>Answer :}}} \\

★ radius of circle = 21 m.

Now we have to find the area of circle, so as we know that the area of the circle is given by,

→ Area = πr²

→ Area = 22/7 × (21)²

→ Area = 22/7 × 21 × 21

→ Area = 22 × 21 × 3

→ Area = 63mutiplied 22

1386 is answer

Answered by prince5132
11

[ 1 ]

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\qbezier(2.3,0)(2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,-2.121)(0,-2.3)\qbezier(2.3,0)(2.121,-2.121)(-0,-2.3)\put(0,0){\line(1,0){2.3}}\put(0.3,0.3){\bf R = 21 m}\put(0,0){\circle*{0.2}}\end{picture}

GIVEN :-

  • radius of Circle , r = 21 m

TO FIND :-

  • The area of Circle.

SOLUTION :-

➳ Area of Circle = πr²

➳ Area of Circle = 22/7 × (21)²

➳ Area of Circle = (22 × 441)/7

➳ Area of Circle = 9702/7

➳ Area of Circle = 1386.

Hence the area of Circle is 1386 .

[ 2 ]

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\qbezier(2.3,0)(2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,-2.121)(0,-2.3)\qbezier(2.3,0)(2.121,-2.121)(-0,-2.3)\qbezier(1.2,0)(1.121,1.121)(0,1.2)\qbezier(1.2,0)(1.121,-1.121)(0,-1.2)\qbezier(0,-1.2)(-1.121,-1.121)(-1.2,0)\qbezier(-1.2,0)(-1.121,1.121)(0,1.2)\put(-0,0){\vector(-1,0){2.3}}\put(0,0){\vector(0,1){1.2}}\put(-2.2,0.2){\bf\small 14\;cm}\put(0.1,0.3){\bf\small 7\;cm}\end{picture}

GIVEN :-

  • Two concentric circles have radii of 14 cm and 7 cm.

TO FIND :-

  • The area of space between them.

SOLUTION :-

Let the radius of smaller circle be "r" and the radius of bigger circle be "R"

➳ Area = πR² - πr²

➳ Area = π(R² - r²)

➳ Area = 22/7 (14² - 7²)

➳ Area = 22/7 (14 × 14 - 7 × 7)

➳ Area = 22/7 (196 - 49)

➳ Area = 22/7 × 147

Area = 462 cm².

Hence The area of space between them is 462 cm².


MisterIncredible: Mind Blowing ( ╹▽╹ )
Similar questions