Solve question no . 13
Answers
Answer:
30 days
Step-by-step explanation:
(i) Work done by (A + B) in 1-day = (1/12).
(ii) Work done by (B + C) in 1-day = (1/15)
(iii) Work done by (C + A) in 1-day = (1/20)
On adding (i),(ii),(iii), we get
2(A + B + C)'s 1-day work = (1/12) + (1/15) + (1/20)
= (5 + 4 + 3)/60
= 1/5
∴ (A + B + C)'s 1-day work = 1/10.
A's 1-day work = (1/10) - (1/15)
= (3 - 2)/30
= 1/30.
Therefore,A alone can complete the work in 30 days.
Hope it helps!
Step-by-step explanation:
(A + B) in 1-day = (1/12).
(B + C) in 1-day = (1/15)
C + A) in 1-day = (1/20)
2(A + B + C)'s 1-day work = (1/12) + (1/15) + (1/20)
= (5 + 4 + 3)/60
= 1/5
(A + B + C)'s 1-day work = 1/10.
A's 1-day work = (1/10) - (1/15)
= (3 - 2)/30
= 1/30.