Math, asked by Anonymous, 11 months ago

Solve question no . 13

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Answered by siddhartharao77
6

Answer:

30 days

Step-by-step explanation:

(i) Work done by (A + B) in 1-day = (1/12).

(ii) Work done by (B + C) in 1-day = (1/15)

(iii) Work done by (C + A) in 1-day = (1/20)

On adding (i),(ii),(iii), we get

2(A + B + C)'s 1-day work = (1/12) + (1/15) + (1/20)

                                         = (5 + 4 + 3)/60

                                         = 1/5


∴ (A + B + C)'s 1-day work = 1/10.

A's 1-day work = (1/10) - (1/15)

                        = (3 - 2)/30

                        = 1/30.



Therefore,A alone can complete the work in 30 days.


Hope it helps!

Answered by Siddharta7
3

Step-by-step explanation:

(A + B) in 1-day = (1/12).

(B + C) in 1-day = (1/15)

C + A) in 1-day = (1/20)


2(A + B + C)'s 1-day work = (1/12) + (1/15) + (1/20)

= (5 + 4 + 3)/60

= 1/5


(A + B + C)'s 1-day work = 1/10.

A's 1-day work = (1/10) - (1/15)

= (3 - 2)/30

= 1/30.

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