Question

Solve question no. 22(i)​

Answer 1

The given question can be rewritten as

$\frac{1}{(\sqrt{7}+\sqrt{6}) - \sqrt{13} }$

Multiplying and dividing by $(\sqrt{7} +\sqrt{6})+ \sqrt{13}$ , we get

$\frac{(\sqrt{7} +\sqrt{6})+ \sqrt{13}}{(\sqrt7+\sqrt6)^2-(\sqrt13)^2}$

$=\frac{(\sqrt{7} +\sqrt{6})+ \sqrt{13}}{7+6+2\sqrt7\sqrt6-13}$

$= \frac{\sqrt6+\sqrt7+\sqrt{13}}{2\sqrt7\sqrt6}$

Multiplying by $\sqrt{42}$ in numerator and denominator

$= \frac{6\sqrt7+7\sqrt6+\sqrt{546}}{84}$

HOPE THIS HELPS!!

Answer 2

Answer:

I hope that helps you.always be happy ☺.