solve Question no 24
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cot A = 4/3 = b/p
therefore h = 5
cosec A = h/p = 5/3
cosec^2A+1/cosec^2A-1
(25/3)+1/(25/3)-1
28/3/22/3
28/22
14/11
therefore h = 5
cosec A = h/p = 5/3
cosec^2A+1/cosec^2A-1
(25/3)+1/(25/3)-1
28/3/22/3
28/22
14/11
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