Question

solve question no.28

Answer 1

HELLO DEAR,



(1+ tan² A) / (1+ cot² A)

= (1+ tan² A) / (1+ 1/tan² A)

= (1+ tan²A) / [(tan² A+ 1)/tan² A)]

= tan² A

and ,

$( \frac{ 1 - \tan( \alpha ) }{1 - \cot( \alpha ) } ) ^{2} \\ = > ( \frac{1 - \tan \alpha }{1 - \frac{1}{ \tan \alpha } } ) ^{2} \\ = > {( \frac{1 - \tan( \alpha ) }{ \tan( \alpha ) - 1} })^{2} \times { \tan( \alpha ) }^{2} \\ = > {( - \frac{\tan( \alpha ) - 1 }{ \tan( \alpha ) - 1} })^{2} \times { \tan( \alpha ) }^{2} \\ = > { \tan( \alpha ) }^{2}$
I HOPE ITS HELP YOU DEAR,
THANKS