Question

solve question no. 35

Answer 1

${(1)}^{2} + (1) - 2 = 0 \\ so \: (x - 1) \: is \: a \:zero \: of \: this \: polynomial \: \: \: |because \: x - 1 = 0 \: so \: x = 1| \\ similarly \: (x + 2) \: is \: also \: a \: zero \\ let \: (x + 1) \: be \: a \: and \: (x + 2) \: be \: \beta \\ so \: \frac{1}{x - 1} - \frac{1}{x + 2} = \frac{x + 2 - (x - 1)}{ (x - 1)(x + 2) } \\ = \frac{3}{(x - 1)(x + 2)}$
i came at this answer but plz confirm it

Answer 2

hi here is ur ans......

(1)

2

+(1)−2=0

so(x−1)isazeroofthispolynomial∣becausex−1=0sox=1∣

similarly(x+2)isalsoazero

let(x+1)beaand(x+2)beβ

so

x−1

1

−

x+2

1

=

(x−1)(x+2)

x+2−(x−1)

=

(x−1)(x+2)

3