Question

solve question no 4 and 5
please solve it step by step☺☺☺☺☺

Answer 1

the population is a town increases by 10% annually.

so population of a year ago =22000-10%of 22000

=22000-10/100×22000

=22000-2200
=19800

question no 5

let income of manoj =x

first increases 20%

so income=x+20%of x

=x+20/100×x
=x+0.2x

=1.2x

then decreases 20%

so income =1.2x -20%of 1.2x

=1.2x-20/100× 1.2x

=1.2x-0.2×1.2x

=1.2x-0.24x

=0.96x


so percentage of income=0.96x/1x ×100%

=96%

so change in percentage of income=100%-96%

=4%



hope its helpful to you


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