Math, asked by sunitapatro307, 1 year ago

Solve question no. 4 ....who will answer first and briefly will marked as brainliest. ....

Attachments:

Answers

Answered by hukam0685
2

a =  \frac{3 +  \sqrt{5} }{2}  \\  {a}^{2}  +  \frac{1}{ {a}^{2} }  = {a}^{2}  +  \frac{1}{ {a}^{2} } + 2 - 2 \\  \\ =  ( {a +  \frac{1}{a} )}^{2}  - 2 \\ \\   =  {( \frac{3 +  \sqrt{5} }{2}  +  \frac{2}{3 +  \sqrt{5} } )}^{2}  - 2 \\  = ( { \frac{3 +  \sqrt{5} }{2} +  \frac{2(3 -  \sqrt{5}) }{(3 +  \sqrt{5})(3 -  \sqrt{5} ) } ) }^{2}  - 2 \\  = ( { \frac{3 +  \sqrt{5} }{2} +  \frac{6 - 2 \sqrt{5} }{9 - 5}  ) }^{2}  - 2 \\  \\  = ( { \frac{6 + 2 \sqrt{5} + 6 - 2 \sqrt{5}  }{4} )}^{2}  - 2 \\  \\  = (  { \frac{12}{4}) }^{2}  - 2 \\  \\   =  {3}^{2}  - 2 \\  = 9 - 2 \\  = 7 \:  \:  \: ans
Similar questions