Question

solve question no. 5 and 7

Answer 1

             

5.

In ΔBCD,

BD = DC

∴ ∠BCD = ∠DBC = 30°

∠ BDC = 180° - (30° + 30°) = 180° - 60° = 120°

∠BDC and ∠BAC are angles on the same chord.

∴ ∠BAC = 180° - ∠BDC = 180° - 120° = 60°

7.

In ΔABC,

AB = AP + BP

&

BC = CQ + BQ

AB = BC

⇒ AP + BP = CQ + BQ

⇒ AP + BP = AP + BQ                 [AP = CQ]

⇒ BP = BQ

Hence proved!!!

Plz ask me if you have any doubts.

Thank you. :-))

#adithyasajeevan