SOLVE QUESTION NO. 54
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Answered by
1
Given that,
a-b = 7.... eq1
ab = 9.....eq2
From eq1 a-b = 7
Therefore (a-b) ^2 = 49
We know that (a-b) ^2 = a^2 + b^2 - 2ab
= 49 = a^2 + b^2 - 2ab
= 49 = a^2 + b^2 - 18 (from eq2 2ab = 18)
= a^2 + b^2 = 49 + 18
= a^2 + b^2 = 67.
So first option is correct.
I am thankful for giving me a chance to help you......
a-b = 7.... eq1
ab = 9.....eq2
From eq1 a-b = 7
Therefore (a-b) ^2 = 49
We know that (a-b) ^2 = a^2 + b^2 - 2ab
= 49 = a^2 + b^2 - 2ab
= 49 = a^2 + b^2 - 18 (from eq2 2ab = 18)
= a^2 + b^2 = 49 + 18
= a^2 + b^2 = 67.
So first option is correct.
I am thankful for giving me a chance to help you......
arya87:
thanks
Answered by
0
given a-b=7
and ab =9
then a^2+b^2= (a-b)^2+ 2ab
a^2+b^2=(7)^2+2(9)
a^2+b^2=49+18
a^2+b^2= 67
option A is correct.
and ab =9
then a^2+b^2= (a-b)^2+ 2ab
a^2+b^2=(7)^2+2(9)
a^2+b^2=49+18
a^2+b^2= 67
option A is correct.
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