✨Solve question no. 6 (ii) ✨
▶ Maths
▶CBSE CLASS 10
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______Heyy Buddy ❤_______
____Here's your Answer ______
L.H.S.
I am taking "A" in place of theta.
sin A ( 1 + tan A) + cos A( 1 + cot A)
=> sin A( 1 + sinA/CosA) + cosA ( 1 + cosA/SinA)
=> SinA ( cosA + sinA)/ cosA + cosA ( sinA + cosA)/sinA
=> SinA + CosA [ sinA/CosA + CosA/ SinA]
=> sinA + cosA [ sin^2A + Cos^2A/ cosA× SinA]
=> SinA + CosA [ 1 / cosA× sinA]
=> sinA/ cosA × sinA. + cosA/ sinA × cosA
=> 1/ cosA + 1/sinA
=> secA + cosecA.
✔✔✔
____Here's your Answer ______
L.H.S.
I am taking "A" in place of theta.
sin A ( 1 + tan A) + cos A( 1 + cot A)
=> sin A( 1 + sinA/CosA) + cosA ( 1 + cosA/SinA)
=> SinA ( cosA + sinA)/ cosA + cosA ( sinA + cosA)/sinA
=> SinA + CosA [ sinA/CosA + CosA/ SinA]
=> sinA + cosA [ sin^2A + Cos^2A/ cosA× SinA]
=> SinA + CosA [ 1 / cosA× sinA]
=> sinA/ cosA × sinA. + cosA/ sinA × cosA
=> 1/ cosA + 1/sinA
=> secA + cosecA.
✔✔✔
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Answered by
1
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