Question

solve question no.8​

Answer 1

Step-by-step explanation:

8.)

=7(7y²-1).......

Answer 2

• GIVEN:-

$\large{\sf{49{y}^{2}-1}}$

• To Find:

Factorisation.

• SOLUTION:-

$\large\Longrightarrow{\sf{49{y}^{2}-1}}$

Using the identity,

$\large\boxed{\sf{{a}^{2}-{b}^{2}}}$

$\large{\sf{Let\: 49{y}^{2} \:be\: a. }}$

$\large{\sf{Let\: 1\:be\: b. }}$

According to the question,

$\large\Longrightarrow{\sf{{a}^{2}-{b}^{2}}}$

$\large\Longrightarrow{\sf{49{y}^{2}-1}}$

$\large\Longrightarrow{\sf{({7y})^{2}-{(1)}^{2}}}$

$\large\Longrightarrow{\sf{(7y+1)(7y-1)}}$

$\huge\blue\therefore\boxed{\sf{\blue{(7y+1)(7y-1)}}}$