Question

solve question no 8 n 9

Answer 1

8)
$6x {}^{2} - x - k = 0$
therefore,
$6 \times (2 \div 3) {}^{2} - (2 \div 3) - k = 0$
$8 - 2 - 3k = 0$
$6 - 3k = 0$
$6 = 3k$
$6 \div 3 = k$
$k = 2$