solve question no. 9,13,14
it's urgent today is my exam
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9. y-(7-8y)/9y-(3+4y) = 2/3
= y-7+8y/9y-3-4y =2/3
=9y-7/5y-3 =2/3
cross multiply
3(9y-7)=2(5y-3)
27y-21=10y-6
17y=15
y=15/17
hope this helps!
= y-7+8y/9y-3-4y =2/3
=9y-7/5y-3 =2/3
cross multiply
3(9y-7)=2(5y-3)
27y-21=10y-6
17y=15
y=15/17
hope this helps!
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