Question

solve question number 1​

Answer 1

Answer:

$\bold{ \tan2A = \cot(A - 18° ) } \\ \\ ⇒ \bold{ \tan2A = \tan[90 - (A - 18°)] } \\ \\ ⇒ \: \bold{2A = 90 - A + 18} \\ \\ ⇒ \: \bold{2A + A = 108} \\ \\ ⇒ \: \bold{3A = 108} \\ \\ ⇒ \: \bold{A = \frac{108}{3} } \\ \\ ⇒ \: \bold{A = 36}$