Question

solve question number 11
full solution
no irrelevant answers ​

Answer 1

Step-by-step explanation:

x=130

no need to mark

see ans

Answer 2

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From Point E let us draw a line EF Parallel to AB and CD.

Since EF || CD and CE is the Transversal

The angles DCE and CEF are Cointerior Angeles then we have

$レDCE + レCEF= 180°$

$⇒x + レCE F = 180°$

$⇒レCEF = 180° - x$

Again EF || AB and AE is the Transversal line Also the angles BAE and AEF are Cointerior Angels then we have

$レB AE + レ AE F = 180°$

$⇒レBA E +レ A EC + CE F \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 180°$

$⇒105° + 25° + 180° - x \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 180°$

$⇒310° - x = 180°$

look at the pic.

✎﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏

mis The answer is in the pic

hame der hoo rahi hai jumma ke liya sorry agr time rheta too pura answer de dete

$\\ \\ \\ \\ \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}$