solve question number 12
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It is not a clear
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siddhartha007:
but its clear dude
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Hello Buddy!!
THe Answer is...
Let equation of any straight line passing through the point of intersection of two given straight line be
k(7x−3y−19)+(3x+2y+5)=0
⇒(7k+3)x+(2−3k)y+(5−19k)=0..[1]
If the straight be parallel to the straight line 2x−y+1=0
then
7k+32=2−3k−1
⇒7k+3=−4+6k
⇒k=−7
Inserting the value of k in [1]
(7⋅(−7)+3)x+(2−3⋅(−7))y+(5−19⋅(−7))=0
⇒−46x+23y+138=0
⇒2x−y−6=0
This is the equation of the required straight line.
#Thanks
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THe Answer is...
Let equation of any straight line passing through the point of intersection of two given straight line be
k(7x−3y−19)+(3x+2y+5)=0
⇒(7k+3)x+(2−3k)y+(5−19k)=0..[1]
If the straight be parallel to the straight line 2x−y+1=0
then
7k+32=2−3k−1
⇒7k+3=−4+6k
⇒k=−7
Inserting the value of k in [1]
(7⋅(−7)+3)x+(2−3⋅(−7))y+(5−19⋅(−7))=0
⇒−46x+23y+138=0
⇒2x−y−6=0
This is the equation of the required straight line.
#Thanks
Mark Me as Brilliant.
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