English, asked by siddhartha007, 11 months ago

solve question number 12

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Answered by ansu82
0
It is not a clear
u send clear image

siddhartha007: but its clear dude
ansu82: It's not clear
siddhartha007: whats that u r not able to understand
siddhartha007: ask me
siddhartha007: i m gonna retype the kuestion
ansu82: I can't understand very well
ansu82: question 12
siddhartha007: thats a separate thing u r not able to understand but i think the picture is not as much blurrr
Answered by Anonymous
0
Hello Buddy!!

THe Answer is...

Let equation of any straight line passing through the point of intersection of two given straight line be

k(7x−3y−19)+(3x+2y+5)=0

⇒(7k+3)x+(2−3k)y+(5−19k)=0..[1]

If the straight be parallel to the straight line 2x−y+1=0

then

7k+32=2−3k−1

⇒7k+3=−4+6k

⇒k=−7

Inserting the value of k in [1]

(7⋅(−7)+3)x+(2−3⋅(−7))y+(5−19⋅(−7))=0

⇒−46x+23y+138=0

⇒2x−y−6=0

This is the equation of the required straight line.

#Thanks

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