Question

solve question number 12 and 13

08278340ac21a6406a13c55f626fe2e1.pdf

Answer 1

$\huge\mathscr\purple{Answer}$

$\sf\pink{12)}$ Assuming that 10cm is meant to be 10m

$a^{2} + {b}^{2} = {c}^{2}$

${a}^{2} + {10}^{2} = {26}^{2}$

${a}^{2} = {26}^{2} - {10}^{2}$

${a \:}^{2} = \: \: 676 \: - \: 100$

${a}^{2} \: = \: 576 \:$

$a \: = \: 24m \:$

$\sf\pink{13)}$ By using pytagorean theorm.

${a}^{2} = \: {b}^{2} + \: {c}^{2}$

${a}^{2} = {12}^{2} + {9}^{2}$

${a}^{2} = 225$

$a = 15km$

Hope it's helps you ☺️

Answer 2

$\huge\mathscr\red{Answer}$

$\sf\pink{12)}$Assuming that 10cm is meant to be 10m

$a^{2} + {b}^{2} = {c}^{2}$

${a}^{2} + {10}^{2} = {26}^{2}$

${a}^{2} = {26}^{2} - {10}^{2}$

${a \:}^{2} = \: \: 676 \: - \: 100$

${a}^{2} \: = \: 576$

$a \: = \: 24m$

$\sf\pink{13)}$ By using pytagorean theorm.

${a}^{2} = \: {b}^{2} + \: {c}^{2}$

${a}^{2} = {12}^{2} + {9}^{2}$

${a}^{2} = 225a$

a = 15km

Hope it's helps you ☺️