Solve question number 16
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Step-by-step explanation:
Given Equation is a²x² - 3abx + 2b² = 0
⇒ a²x² - 2abx - abx + 2b² = 0
⇒ ax(ax - 2b) - b(ax - 2b) = 0
⇒ (ax - b)(ax - 2b) = 0
⇒ x = (b/a), x = (2b/a)
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1
a²x²-3abx+2b²
= a²x²-2abx+b²+b²-abx
= (ax-b)²-b(ax-b)
= (ax-b)(ax-b) - b(ax-b)
= (ax-b)(ax-b-b)
= (ax-b)(ax-2b)
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