Solve question number 2(d) and (e)....Both the answers are false..I just want the reasons..
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Multiplying or dividing the same number on both sides of an inequality doesn't change the inequality(provided the multiplying or dividing number is not zero)
Shaik96:
Take c as a number <0 u will get the answers
I assumed that C>0
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D. Suppose a= 2 and b= 3.
a<b because 2<3.
Multiply both by any number where c does not equal to 0.
Let c= 2/3/4/...
2*2< 3*2
4<6.... Similarly..
ac<bc.
E. Similarly as D, a= 3 and b=1.
a>b because 3>1.
Divide both sides by any number. For example 1.
3/1 > 1/1
3>1...
a/c > b/c.
Hope it's helpful to u.
a<b because 2<3.
Multiply both by any number where c does not equal to 0.
Let c= 2/3/4/...
2*2< 3*2
4<6.... Similarly..
ac<bc.
E. Similarly as D, a= 3 and b=1.
a>b because 3>1.
Divide both sides by any number. For example 1.
3/1 > 1/1
3>1...
a/c > b/c.
Hope it's helpful to u.
but both the answers are false. It is mentioned in the book.
Answer of d-false
answer of e-false
This is only applicable for c>0. for c<0 then the inequality gets changed
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