solve question number 3
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CaCO3 decomposes as : CaCO3 -> CaO + CO2
1.135 L of CO2 contains 1.135/22.4 moles = 0.05
Molar mass of CaCO3 = 100
Thus 0.05 moles of CaCO3 will weigh 0.05*100 = 5g
1.135 L of CO2 contains 1.135/22.4 moles = 0.05
Molar mass of CaCO3 = 100
Thus 0.05 moles of CaCO3 will weigh 0.05*100 = 5g
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