Solve Question of iit jee
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Answered by
17
Answer:
|ab+bc+ca| = -25 Option (c) is correct
Step-by-step explanation:
Given :- |a| = 5 , |b| = 4 , |c| = 3
- a+b+c= 0
- (a+b+c)² = 0²
- a²+b²+c²+2ab+2bc+2ca = 0
- 5²+4²+3² +2(ab+bc+ca)
- 25 + 16 +9 = -2(ab+bc+ca)
- (ab+bc+ca) = -50/2 = -25 Answer
Answered by
60
Given :-
To find :-
Solution :-
Answer :-
Option (a) 25 is correct
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