solve question of mathematics question 2
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Hii !!
Common difference ( D ) = 4
10th term = 43
a + 9d = 43
a + 9 × 4 = 43
a + 36 = 43
a = 43 - 36
a = 7..
First term ( a ) = 7
Therefore,
5th term = a + 4d = 7 + 4 × 4 = 7 + 16 = 23
and,
8th term = a + 7d = 7 + 7 × 4 = 7 + 28 = 35
Common difference ( D ) = 4
10th term = 43
a + 9d = 43
a + 9 × 4 = 43
a + 36 = 43
a = 43 - 36
a = 7..
First term ( a ) = 7
Therefore,
5th term = a + 4d = 7 + 4 × 4 = 7 + 16 = 23
and,
8th term = a + 7d = 7 + 7 × 4 = 7 + 28 = 35
Answered by
0
Hey!!
Given
Common Difference ( d ) = 4
a10 = 43
=> a + 9d = 43
Given d = 4
Substitute d = 4
=> a + 9 ( 4 ) = 43
=> a + 36 = 43
=> a = 43 - 36
=> a = 7
First term a1 = 7
a5 = a + 4d = 7 + 4 ( 4 ) = 7 + 16 = 23
a8 = a + 7d = 7 + 7 ( 4 ) = 7 + 28 = 35
Therefore the 5th of an A.P is 23 and the 8th of an A.P is 35.
Hope it helps!
Given
Common Difference ( d ) = 4
a10 = 43
=> a + 9d = 43
Given d = 4
Substitute d = 4
=> a + 9 ( 4 ) = 43
=> a + 36 = 43
=> a = 43 - 36
=> a = 7
First term a1 = 7
a5 = a + 4d = 7 + 4 ( 4 ) = 7 + 16 = 23
a8 = a + 7d = 7 + 7 ( 4 ) = 7 + 28 = 35
Therefore the 5th of an A.P is 23 and the 8th of an A.P is 35.
Hope it helps!
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