Question

solve question plzz​

Answer 1

Answer:

let the digits be a,a+d,a+2d

given sum of digits=3a+3d=15

a+d=5.....1

and (a+2d)100+(a+d)10+a=(a)100+(a+d)10+(a+2d)-594

100a+200d+a=100a+a+2d-594

198d=-594

d=-3

from equation 1

a+d=5

a-3=5

a=8

therefore the digits are 8,5,2

the number is 852

Step-by-step explanation:

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Answer 2

Answer:

$refer \: to \: attachment \: \: and \: no \: is \: 852$