Question

solve questions no 9

Answer 1

Velocity in glass = 2*10^8m/s
Velocity in air= 3*10^8m/s

Therefore,
Refractive Index of glass with respect to air= (3*10^8) /(2*10^8)= 1.5

The ink dot is of negligible thickness, hence the thickness of the glass plate is the real depth.

According to the formula for real depth and apparent depth,

Refractive Index of glass with respect to air
=Real depth/ Apparent depth

1.5= 6/Apparent depth
Apparent depth = 6/1.5
Apparent depth = 4 cm
Now, question asks for how much the dot is raised i.e, it's shift

Shift= 6-4
Shift = 2cm

Hence, the ink dot appears to be raised by 2cm...
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