Question

solve quick class 7 chapter 7 simple linear equation​

Answer 1

Answer:

Largest integer = 23

Step-by-step explanation:

Question:-

• The sum of three consecutive odd integers is 63. What is the largest integer?

Solution:-

To Find:-

• Largest integer?

Assume:-

• First consecutive odd integer = n
• Second consecutive odd integer= n+2
• Third consecutive odd integer= n+4

According to the question

→ n+n+2 +n+4 = 63

→ 3n + 6 = 63

→. 3n = 63-6

→. 3n = 57

→. n = 57/3 =19

So,

• First consecutive odd integer= n= 19
• Second consecutive odd integer= n+2 = 19+2 = 21
• Third consecutive odd integer= n + 4 = 19+4 = 23

And largest integer = 23

_________________________

Another info:-

• Consecutive numbers - Numbers which follow each other continuosly. Ex. - x,x+1,x+2,x+3 etc.

Answer 2

$\blue\star$ Given :

• Sum of three consecutive odd integers = 63.

$\red\star$ To find :

• The largest integer among them.

$\pink\star$ Solution :

Let the integers be x, x + 2 and x + 4

A/q

$\sf \: x \: + \: x \: + 2 \: + \: x \: + \: 4 \: = \: 63 \\ \implies \: \sf \: 3x \: + \: 6 \: = \: 63 \: \\ \sf \implies \: 3x \: = \: 57 \\ \sf \: \implies \: x \: = \: \frac{57}{3} \\ \sf \: \implies \: \boxed{ \sf x \: = 19}$

If x = 19, then,

x + 2 = 21

x + 4 = 23

So, the integers are 19, 21 and 23 .

$\therefore$ The largest integers among them is 23.

$\green\star$ More to Know :-

• Here, we assumed x as odd, therefore it's next odd consecutive integer will be x + 2 and so on, not x + 1 because it'll give rise to consecutive even integer, not the odd integer.

• Here, if we'll add 19, 21 and 23, we'll get the sum as 63, as given in question. Hence, it is verified too.