Question

solve rationalisation 6√5-5√3/2√3+4√5​

Answer 1

Answer:

6√5-5√3/2√3+4√5 = 6√5-5√3/2√3+4√5 × 2√3-4√5/2√3-4√5 = (6√5-5√3)×(2√3-4√5)/(2√3+4√5)×(2√3-4√5) = 12√15-120-30+20√15/4×3-16×5 = 32√15-150/12-80 = 2(16√15 -75)/-68 = 16√15 -75/-34 = - 16√15-75/34