Question

Solve....................
Remainder in
${2}^{100} \div 7$

Answer 1

Hello friend
The question is good .. I gave u brief description about this type of questions.. from which you can solve more questions like that .
2×(2^3)^33 = 2^100
2×(8)^33
2×(7+1)^33
When we expand any polynomial equation see in the uploaded picture
U can see that every terms containing x and y , except first and last term ..
Here x=7 , y=1
When we devide (7+1)^33 by 7 .. only last term will not devide .. so the reminder for last term is 1 but it is multipliy by 2 ..
Final reminder = 2×1 = 2
Hope it will help you !!