Question

solve root 11x+root 3y=0 root 5x-root11y=0

Answer 1

Answer:

let

$\sqrt{11} x + \sqrt{3} y = 0....(i) \\ \\ \sqrt{5} x - \sqrt{11} y = 0.....(ii)$

now from equation (i)

$\sqrt{11} x = - \sqrt{3} y \\ x = \frac{ - \sqrt{3} }{ \sqrt{11} } y$

$\sqrt{11} x = - \sqrt{3} y \\ x = \frac{ - \sqrt{3} }{ \sqrt{11} } y \\ x = \frac{ - \sqrt{3} }{ \sqrt{11} } \times 0 \\ x = 0$

putting this value of X in equation (ii)..

we got

$\sqrt{5} \times \frac{ - \sqrt{3}y }{ \sqrt{11} } - \sqrt{11} y = 0 \\ - \sqrt{15 } y - 11y = 0 \\ y( - \sqrt{15} - 11) = 0 \\ y = \frac{0}{\sqrt{15} - 11) }$

y=0

now from eqation i

x=

$\sqrt{11} x = - \sqrt{3} y \\ x = \frac{ - \sqrt{3} }{ \sqrt{11} } y \\ x = \frac{ - \sqrt{3} }{ \sqrt{11} } \times 0 \\ x = 0$