Question

Solve: root 2x-6+ root x+4 = 5.​

Answer 1

Answer:

Square both sides:

(2x - 6) + (x + 4) + 2 sqrt ((2x - 6)(x + 4)) = 25

Then isolate the remaining square root term:

2 squareroot ((2x - 6)(x + 4) = 27 - 3x

Then square both sides:

4 (2x - 6)(x + 4) = 729 - 162x + 9x²

Expand:

8x² + 8x - 96 = 729 - 162x + 9x²

Put all on one side:

x² - 170x + 825 = 0

Solve by quadratic formula or otherwise:

x = (170 +/- sqrt (170² - 3300)) / 2

= (170 +/- 160) / 2

= 5 or 165.

But for some reason 165 doesn't work, so x = 5.

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hope it helps..

Please mark me as brainliest

Answer 2

Square both sides:

(2x - 6) + (x + 4) + 2 sqrt ((2x - 6)(x + 4)) = 25

Then isolate the remaining sqrt term:

2 sqrt ((2x - 6)(x + 4) = 27 - 3x

Then square both sides:

4 (2x - 6)(x + 4) = 729 - 162x + 9x²

Expand:

8x² + 8x - 96 = 729 - 162x + 9x²

Put all on one side:

x² - 170x + 825 = 0

Solve by quadratic formula or otherwise:

x = (170 +/- sqrt (170² - 3300)) / 2

= (170 +/- 160) / 2

= 5 or 165.

But for some reason 165 doesn't work, so x = 5.

..

....

......

hope it helps...

plZz Mark as a brainliest!!

R