Question

solve root 3 cosx-sinx=1

Answer 1

Hope u like my process
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$= > \sqrt{ 3} \cos(x) - \sin(x) = 1 \\ \\ dividing \: \: \: both \: \: \: sides \: \: \: by \: \: 2 \\ ............................................ \\ \\ = > \frac{ \sqrt{3} }{2} \cos(x) - \frac{1}{2} \sin(x) = \frac{1}{2} \\ \\ = > \sin( \frac{\pi}{3} ) \cos(x) - \cos( \frac{\pi}{3} ) \sin(x) = \frac{1}{2} \\ \\ = > \sin( \frac{\pi}{3} - x ) = \sin( \frac{\pi}{6} ) \\ \\ = > \frac{\pi}{3} - x = \frac{\pi}{6 } \\ \\ = > x = \frac{\pi}{3} - \frac{\pi}{6} = \frac{\pi}{6}$
So...

$x = \frac{\pi}{6} = 30 \: \: degrees$
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