Math, asked by muskan3831, 1 year ago

Solve (root 6)^x-2=1

Answers

Answered by Anonymous
6

Answer: 2

Step-by-step explanation:

Concept: Zero Exponent rule

The zero exponent rule, often known as the zero property of exponents states that a numerical value of any number "a" raised to the power zero is always one, hence any such number will always equal one.

Given:  (root 6)^x-2=1

To Find: value of x

(6√)^x-2=1

we can write as (6√)^0, as per the zero exponent rule i.e. a^0=1

(6√)^x-2=(6√)^0

Using the coefficient comparison, we get

x-2=0

x=0+2

x=2

Hence, the value of x in the given problem (root 6)^x-2=1 is 2.

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Answered by VishwachiT
1

Answer:

x =2

Step-by-step explanation:

By using the zero exponent rule which states that the numerical value of any number a raised to zero, will always be 1, we get:

(\sqrt{6} )^x^-^2 = 1

(\sqrt{6} ) ^x^-^2 = (\sqrt{6} )^0

Therefore, comparing the power coefficients on both sides we get,

x-2 = 0

x = 2.

#SPJ1

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