Solve: root2x - 6+ root x+4 = 5.
Answers
Square both sides:
(2x - 6) + (x + 4) + 2 sqrt ((2x - 6)(x + 4)) = 25
Then isolate the remaining sqrt term:
2 sqrt ((2x - 6)(x + 4) = 27 - 3x
Then square both sides:
4 (2x - 6)(x + 4) = 729 - 162x + 9x²
Expand:
8x² + 8x - 96 = 729 - 162x + 9x²
Put all on one side:
x² - 170x + 825 = 0
Solve by quadratic formula or otherwise:
x = (170 +/- sqrt (170² - 3300)) / 2
= (170 +/- 160) / 2
= 5 or 165.
But for some reason 165 doesn't work, so x = 5.
..
....
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hope it helps...
plZz Mark as a brainliest!!
Answer:
Square both sides:
(2x - 6) + (x + 4) + 2 sqrt ((2x - 6)(x + 4)) = 25
Then isolate the remaining sqrt term:
2 sqrt ((2x - 6)(x + 4) = 27 - 3x
Then square both sides:
4 (2x - 6)(x + 4) = 729 - 162x + 9x²
Expand:
8x² + 8x - 96 = 729 - 162x + 9x²
Put all on one side:
x² - 170x + 825 = 0
Solve by quadratic formula or otherwise:
x = (170 +/- sqrt (170² - 3300)) / 2
= (170 +/- 160) / 2
= 5 or 165.
But for some reason 165 doesn't work, so x = 5.
..
....
......
hope it helps...
plZz Mark as a brainliest!!