Question

solve root3 cot theeta-2cos theeta=0​

Answer 1

To Evaluate: √3 cot∅ - 2 cos∅ = 0

→ √3 cot∅ - 2 cos∅ = 0

→ √3 cos∅/sin∅ - 2 cos∅ = 0

→ (√3 cos∅ - 2 cos∅ sin∅)/sin∅ cos∅ = 0

→ √3 cos∅ - 2 cos∅ sin∅ = 0

→ √3 cos∅ = 2 cos∅ sin∅

→ √3 = 2 sin∅

→ √3/2 = sin∅

Since sin 60° = √3/2

→ sin∅ = sin 60°

→ ∅ = 60°

Hence value of ∅ is 60°.