Question

solve = s/x-1 + 1/y-2 = 2, 6/x-1 - 3/y-2 = 1

Answer 1

Hiii friend,

5/X-1 + 1/Y-2 = 2......(1)

6/X-1 - 3/Y-2 = 1.......(2)


Putting 1/X-1 = U and 1/Y-2 = V.


5U + V = 2.......(3)


6U - 3V = 1........(4)

From equation (3) we get,


5U + V = 2


V = 2-5U......(5)

Putting the value of V in equation (4)

6U - 3V = 1


6U - 3 × (2-5U) = 1


6U -6 + 15U = 1


21U = 1+6


21U = 7


U = 7/21 = 1/3


Putting the value of U in equation (5)


V = 2-5U

V = 2- 5 × 1/3 = 2-5/3 = 6-5/3 = 1/3


Therefore,


1/X-1 = U

1/X-1 = 1/3

3 = X-1


X = 3+1 = 4


And,


1/Y-2 = V


1/Y-2 = 1/3


3 = Y-2


Y = 3+2


Y = 5.


Hence,

X = 4 and Y = 5.



HOPE IT WILL HELP YOU...... :-)