Solve (sec-tan)²
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Answer:
The question is (secA-tanA)
Step-by-step explanation:
LHS
=(secA−tanA)^2
=(cosA 1−cosA sinA)^2
= (1−sin2A)(1−sinA)^2
=(1−sinA)(1+sinA)(1−sinA)^2
= 1+sinA 1−sinA
=RHS
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